Calcrete
Structural work

Asphalt Calculator

Asphalt volume and short tons from supplied density.

Volume with allowance
2.037 yd³
Net volume
1.852 yd³
Extra volume
0.185 yd³
Weight with allowance
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Enter density to calculate weight
US short tons (2,000 lb)
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Material cost
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Excludes delivery and accessories

How it works

Volume is calculated from the selected geometry or quantity. Compaction and purchasing allowances are applied separately. Weight is only available when you provide density.

volume = area × depth; weight = volume × density

How the Asphalt Calculator works

This asphalt calculator estimates the volume of a measured pavement layer and its weight using your mixture density. It supports cubic yards, pounds and clearly labelled US short tons.

Calculate a measured layer

A 1,000 ft² area at 2 in average thickness occupies 166.667 ft³, or 6.173 yd³. If the supplied density is 145 lb/ft³, the theoretical net mass is 24,166.7 lb, or 12.083 short tons. With 5% extra allowance and no compaction addition, that becomes 12.688 short tons. The density here is an example input.

Use the correct material condition

Density must refer to the condition represented by the volume. For a compacted layer and compacted-mixture density, leave extra compaction at zero unless the supplier specifies a separate correction; adding a loose-volume factor again can double count the adjustment.

Thickness and mix selection come from the pavement plan. Irregular patches need separate average depths. Aggregate base can be estimated in the gravel calculator; it is not included in the asphalt result. Material price per cubic yard excludes trucking and installation.

FAQ

How many pounds are in an asphalt ton? expand_more

The US result uses one short ton = 2,000 lb. The metric-unit result instead uses tonnes of 1,000 kg.

Why does this need density? expand_more

Geometry supplies volume. Different mixtures and material conditions have different weights for that volume.

Can I calculate a circular patch? expand_more

Calculate its area as π × radius², choose known area, and enter the average layer thickness.